Equivalent Networks and Superposition Pre Lab 3

Part (A):

  • For Node (1):

(V1-10)/1000+ (V1-V2)/1000+ V1/(5.1 x 1000)=0  (1)

  • For Node (2):

(V2-V1)/1000+ V2/(3.3 x 1000)=0  (2)

  • Solve equations (1) and (2) to find the values of V1 and V2 by using the calculator:

V1= 6.99968 V

V2= 5.37185 V

Vth = V2 = 5.37185 V

  • The circuit is open so there is no current in a & b :

Req1 = 1 kW // 5.1 kW

= 836.066 W

Req2 = Req1 + 1 kW

= 836.066 + 1000 = 1836.07 W

Req3 = Req2 // 3.3 kW

= = 1179.7 W

Req4 = Req3 + 1 kW

= 1179.7 + 1000 = 2179.7 W

Rth = Req4 = 2179.7 W

  • The current through the 2 kW resistor:

I 2kW =

= = 0.001285 A

I 2kW = 1.285 mA

Part (B):

Figure 1 below shows circuit (B) done by the PSPICE.

Equivalent networks and superposition pre lab 3 Image 1

Figure 1: Circuit (B)

Part (C):

  • My Netlist:

V-V1 N001 0 10V

R_R1 N002 N001 1k W

R_R2 N003 N002 1k W

R_R3 N004 N003 1k W

R_R4 0 N002 5.1k W

R_R5 0 N003 3.3k W

R_RL 0 N004 2k W

  • The PSPICE Netlist:
Equivalent networks and superposition pre lab 3 Image 2
  • The difference between the PSPICE Netlist and my Netlist is the choice of nodes.

Part (D):

  • By using the Mesh current method:
  • Loop (1):

15 + 5.1 x 103*I1 + 2x103 (I1 – I2) =0 à (1)

  • Loop (2):

-1x103*I2 – 2x103 (I2 – I1) – 5.1x103 (I2 – I3) = 0 à (2)

  • Loop (3):

5.1x103 (I3 – I2) + 2x103*I3 – 1.5 = 0 à (3)

  • Solve equations (1), (2) and (3) to find the values of I1, I2 and I3 by using the calculator:

I1 = 0.002342 A

I2 = 0.000813 A

I3 = 0.000373 A

VL = I2 x 1 kW

VL = -0.000813 x 1000 = 0.813 V

Part (E):

Figure 2 below shows circuit (E)

Equivalent networks and superposition pre lab 3 Image 3

Figure 2: Circuit (E)

Part (F):

Figure 3 below shows circuit (F)

Equivalent networks and superposition pre lab 3 Image 4

Figure 3: Circuit (F)

Table 1 below shows the calculation for VL for part (D, E, F).

VL (voltage over the 1 kW resistor)

Calculation Part D

(No diode)

PSPICE Part E

(No diode)

PSPICE Part F

(with diode)

1.V1 & V2 Present

0.813

0.813

3.275

2.V1 only

1.091

1.091

2.881

3.V2 only

-0.278

-0.2782

7.151x10-6

4.Add line 2&3

0.813

0.8128

2.88099

5.% difference between line1 and line4

0%

0.0246 %

26.5347%

Table 1: The Values of VL

  • The % difference formula:

For example:

% difference= x 100%= 0%


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