Solution
Ht^{2} =15^{2} + 8^{2}, HT^{2} = 289, HT= √ (289), HT =17
COS (T) = 8/17, <T = COS^{-1 }(8/17), <T cos-1(0.4706) = 61.9 ^{0}
<T = 61.9 ^{0}
Solution
To calculate the area of the above triangle we will use the formula,
Area = ½ *a*b * sin (c) ,where a and b are any two given sides of the triangle and c is the angle between the two sides thus
Area = ½ *7*13* sin (38), 1/2*7cm*13cm*sin (38) = 28.0126 cm^{2}
Solution
First we put the given information into a diagram
We know Sin x = opposite side /hypotenuse side, cos x = adjacent side /hypotenuse
Thus this is a triangle with opposite side =15, adjacent side = 8 and hypotenuse =17
Also it’s a right angled triangle since 8^{2} = 15^{2} =17^{2}=289
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