According to Hooke’s Law, F = ks when a body of mass m is suspended on a spring with spring constant k, and the spring is stretched or compressed from equilibrium position with displacement s.
F is a restoring force, the negative sign in the equation indicating force is always opposite to the direction of displacement. If the spring is hung vertically, application of Newton’s First Law means that F = mg. Combining Hooke’s Law with F = mg, we get mg = ks. Using this combined equation, we can determine the spring constant k for Part 1 of the experiment. The displacement for Part 1 was obtained using a motion sensor, measuring the distance between the weight hanger and the sensor.
A body that is stationary is in equilibrium. If a body of mass m is displaced from equilibrium with distance x, there will be a net force acting on the body. According Newton’s Second Law, this net force will cause the object to oscillate up and down around the system’s equilibrium position. The total mechanical energy for a vertically oscillating springmass system is E_{mech} = 1/2mv^{2} + 1/2k(x_{0}x)^{2} = mgx. In this equation, kinetic energy of the mass, elastic potential energy of the spring, and gravitational potential energy are all accounted for. x_{0} is the distance the spring is stretched with a mass on it. Further derivable equations are as followed:
E_{mech} = 1/2mv^{2} + 1/2k((mg/k)x)^{2} + mgx
E_{mech} = 1/2mv^{2} + 1/2kx^{2} + (mg)^{2}/2k
For the equation below, h_{0} is the distance between the motion sensor and the spring with no motion. When there is no motion, the distance from the detector is measured as h.
E_{mech} = 1/2mv^{2} + 1/2k(hh_{0})^{2} + (mg)^{2}/2k
Because (mg)^{2}/2k is a constant, the sum of the first two terms on the right side of the equation directly above must remain the same for equilibrium to be conserved.
For part 1 of the experiment, we measured the spring constant k. For part 2 of the experiment, we experimentally verified the conservation of mechanical energy of a springmass system. The motion sensor was used to detect oscillation and a graph of distance h with velocity v. time for the system was obtained. Using manual calculation and verifying manual calculations with software generated data, we were able to confirm energy is conserved at every point in time for the vertically oscillating springmass system.
Part I. Spring Constant Measurement
Part II. Verification of Conservation of Mechanical Energy of a SpringMass System
4.1 Experimental Data
Table1
M (mass of weight hanger) = 0.08486 kg
Weight(N) 
Mg 
Mg+ 100g 
Mg+ 200g 
Mg+ 300g 
Mg+ 400g 
Mg+ 500g 
Position y_{i}(m) 
y_{0} 
y_{1} 
y_{2} 
y_{3} 
y_{4} 
y_{5} 
0.503 
0.475 
0.434 
0.413 
0.353 
0.313 

Displacement y_{0}y_{1}(m) 
0 
0.028 
0.069 
0.09 
0.15 
0.19 
As can be seen in the graph, k has been estimated to equal 25.263 N/m.
Table2
m = M + 0.25 kg = 0.33486 kg
(h_{0}) = 0.413 m
Equilibrium Position
Point # 
Displacement X=hh_{0} (m) 
Velocity v (m/s) 
KE = mv^{2}/2 (J) 
PE = kx^{2}/2 + m^{2}g^{2}/(2k) (J) 
ME = KE + PE (J) 
1 
0.037 
0.004 
2.7 x 10^{6} 
0.231 
0.231 
2 
0 
0.319 
0.017 
0.214 
0.231 
3 
0.038 
0.004 
2.7 x 10^{6} 
0.232 
0.232 
Capstone Program Graph
4.2 Calculations
Table 1 calculations were relatively simple. Since y_{i} was measured to be 0.503 m, to find further y_{n}s, I simply did y_{n }– y_{i} to get each of the displacement values in the table. Since the spring system in part 1 was at rest, the relationship F_{g }= F_{s} would hold true, meaning F_{g} = kx. I then graphed values of F_{g} v. displacement to get a linear graph with a slope of value 25.263 N/m. r
Table 2 calculations were relatively simple as well. Displacement and velocity were read off of the screen for 3 points, point 1 referring to a peak of position, point 2 referring to a position of near 0 displacement, and point 3 referring to a trough of position. Using this data, I then plugged in values of mass, velocity, spring constant, displacement and energy values to get the remaining three columns of data. Sample calculations for Point 1 are as followed:
Sample KE calculation:
KE = mv^{2}/2
KE = (0.33486 kg)( 0.004 m/s)^{2}/2
KE = (0.33486)(1.6 x 10^{5})/2
KE = 2.7 x 10^{6} J
Sample PE calculation:
PE = kx^{2}/2 + m^{2}g^{2}/(2k)
PE = (25.263 N/m)( 0.037 m)^{2}/2 + (0.33486 kg)^{2}(9.81m/s^{2})^{2}/(2(25.263 N/m))
PE = (25.263)( 0.0014)/2 + (0.1121)(96.24)/50.53
PE = 0.231 J
Sample ME calculation:
ME = KE + PE
ME = (2.7 x 10^{6} J) + (0.231 J)
ME = 0.231 J
4.3 Error Analysis
There was some error in the program generating Mechanical Energy measurements. ME reached a max value of 13.952 J and a minimum value of 13.94 J. Percentage difference between the two values is calculated below:
E_{abs} = max value – min value
E_{abs} = 13.952 J – 13.94 J = 0.012 J
13.952 J ± 0.012 J
E_{rel} = E_{abs }/min value
E_{rel} = 0.012 J /13.94 J
E_{rel} = 0.1%
The prediction of total energy was not close at all to the experimental result. My group did not perform the lab correctly, forgetting (in Part II) to input the k constant and mass of the hanging mass into the program for accurate graphs of PE, KE, and ME. Had we performed the done so, the results probably would have been a lot more accurate as a reflection of experimental results. Knowing that, the error calculation between the maximum and minimum values of the returned ME graph from the program was not really applicable to our experiment, but the relationship between KE, PE, and ME in the graph would hold true even with different k constant and mass values. Were the experiment to be performed again, I would suggest more closely monitoring the experimental procedure and making sure that all technical details are taken care of.
Besides that, sources of error could have included errors of reading the measurements on the screen, error in manually recording and measuring data, error in setting up the experiment, using the wrong weight amounts, failing to check for possible defects in equipment like a broken spring or weight hanger, among other things. Systematic error could have occurred because supposing the massing device was not zeroed properly, or the sensor was tilted a little askew from the line of motion, results could have been skewed up or down, depending. Random errors could have occurred as well. Part I was supposed to be a springmass system under equilibrium, and sometimes, the system shook a little. Some trials were not performed as carefully as others, and it was difficult to make sure that for Part II, the springmass system oscillated completely vertically. For that reason, there could have been an increased error with results when motion was added in the equation, either motion in the wrong directions, or increased motion when there should have been none.
Looking at the mechanical energy graph generated by the capstone program, there is a little variance in the total mechanical energy. The difference is not big, the line of data is just a little variable. Percentage difference was calculated to be 0.1% as seen above in the error section, but as explained before, this data is not really applicable to our experiment because we failed to input a k constant and the mass as needed for accurate KE, PE, and ME graphs.
As this lab is concluded, I now know how to test for the k value, total mechanical energy, kinetic energy and potential energy of a springmass system using a force sensor. I also know how to verify the conservation of mechanical energy in a springmass system. We did not perform the second part of the lab correctly, but in any given springmass system, the relationships in the KE, PE, and ME graphs will be the same under simple harmonic motion. Since I performed the theoretical calculations and understand how they work, I have come through with an understanding about how to accurately perform the lab, were it to be done again and of the underlying concepts the lab tries to teach. Next time, I would be sure to look more closely at the procedure and take precautionary measures that nothing is missed.
For this lab, we performed 5 trials for Part 1 of the lab to observe the relationship described by Hooke’s Law, where F_{s} = kx. Since under a condition of equilibrium a mass spring system doesn’t move, the forces balance out, mg = kx. So F_{g} = kx, which was graphed using Excel, the slope of the line determined to be the spring constant. Hooke’s Law was thus confirmed. For Part II of the experiment, various equations were confirmed to check for the relationship between KE, PE, and ME. Using a system of an oscillating mass, position and velocity measurements were taken at 3 positions, when the peak of position was reached, when the average of position was reached, and when the trough of position was reached. Using equations KE = mv^{2}/2, PE = kx^{2}/2 + m^{2}g^{2}/(2k) and ME = KE + PE, I manually calculated the given energy values and was able to confirm the relationship between these three equations, where under every point of motion in an energy curve for an oscillating springmass system, KE + PE = ME, and energy is conserved.
Our motto is deliver assignment on Time. Our Expert writers deliver quality assignments to the students.
Get reliable and unique assignments by using our 100% plagiarismfree services.
The experienced team of AssignmentHippo has got your back 24*7. Get connected with our Live Chat support executives to receive instant solutions for your assignment problems.
We can build quality assignments in the subjects you're passionate about. Be it Programming, Engineering, Accounting, Finance and Literature or Law and Marketing we have an expert writer for all.
Get premium service at a pocketfriendly rate. At AssignmentHippo, we understand the tight budget of students and thus offer our services at highly affordable prices.