Let one of the integer be x
The other integer will be 5x-3
Therefore; x(5x-3) = 36
5x^{2}-3x-36=0
Therefore, x=3
Hence the integers are 3 and 5(3)-3=12
2) The width of a rectangle is 5 units less than the length. If the area is 150 square units, then find the dimensions of the rectangle.
Let the length of the rectangle be x units
Width will be x-5 Units
X(x-5) = 150
5x^{2}-3x-36=0
Therefore, x = 15
Hence; The dimensions are;
Length = x units = 15 units
Width = x-5 = 15-5 = 10units
Let the width = x
Length = x+4
Area = 3xPerimeter+5
X(x+4)=2(2(l+b)+5)
X^{2}+4x=4(2x+4)+5
x^{2}-4x-21=0
Therefore, length = x+4 = 7+4 = 11 inches
Width = x = 7 Inches
Let h = 0, since height of the ground is zero.
−16𝑡^{2}+32𝑡+128=0
-16(t+2)(t-4)=0
t = -2 or t = 4
Time cannot be a negative value so we ignore t = -2
Therefore, the projectile will hit the ground in 4 Seconds.
The ball will hit the ground at h=0
−16𝑡^{2}+144 = 0
T^{2}=9
t = 3 Seconds
Therefore; The ball will hit the ground in 3 Seconds.
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