Provide solution to the following questions:
This question requires integration by parts
Let u=x and dv/dx =sin (3x)
du=x dx=1
But
Substitute y=mx+1 in =4x
= 4x
Expanding = 4x
+1+2mx-4x=0
+x(2m-4)+1=0
The tangent touches the curve at one point hence the roots are equal. Therefore, discriminant =0
-4((1) = 0
+16-16m-=0
16-16m=0
16=16m
M=1
Te integrating factor of the equation is
x − y +2z =7
3x +4y −5z =−5
2x − y + 3z = 12
Hence
X=2
Y=1
Z= 3
Reference
Chirgwin, B., & Plumpton, C. (2016). A course of mathematics for engineers and scientists. Elkins Park: Pergamon Press/Elsevier Science.
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