The error norm comparisons are shown the tables

D NN=0.0247

The transfer function of the identified filter is:

T		z =	0.02469 z 5		+0.1231z			4	+ 0.246 z 3			+ 0.2431 z 2			+0.1196 + z
NN			z 5	- 1.104 z		4	+ 1.607 z			3	- 1.163 z		2	+ 0.6461 - z

Table 5.1: Error Norms of Example 5.1 under Noise Free Conditions

	N. N.	Lease Square	Subspace
ε2	3.90e-03	3.67e-15	1.93e-15
ε∞	2.77e-3	3.77e-15	2.52e-15

Table 5.2: Error Norms of Example 5.1 under White Noise Conditions

	N. N.	Lease Square	Subspace
ε2	3.52e-02	8.30e-2	4.95e-2
ε∞	3.56e-2	7.15e-2	3.71e-2

	N. N.	Lease square	Subspace
ε2	5.34r-2	1.21e-01	9.07e-2
ε∞	5.29e-2	8.98e-2	6.48e-2

A =		B
C = 0 0.5373 0.4676 [ ]		B

The corresponding transfer function is as follows:

T(z)	=		0.5781 z			2	+	0.1419 z
		z	3	+	0.2149 z			2	+

NN

3 0 2139 + .

z	2	+	0 4284 .

−0 3536 .

	N. N.	Lease square	Subspace
ε2	3.69e-4	1.47e-15	1.26e-15
ε∞	3.83e-4	1.20e-15	9.60e-16

Over 10 Million Study Resources Now at Your Fingertips